∴∠CHE = ∠HCB – 120° ———- (i) [Alternate interior angles] In the given figure, QP || RS. The difference of two complementary angles is 30°. Thus, one angle is 45° and other is 180° – 45° = 135°, Question 98. Since, sum of all the angles on a straight line is 180°. (c) four pairs of adjacent angles. If the sum of measures of two angles is 90%, then the angles are _________ As, if we subtract an acute angle from 180°, we get an angle which is greater than 90°. Now, l is also parallel to CD and FG is a transversal. 2x + 1 + 2x + 3 = 180° Measure of a right angle is 90°. Now, RS is a straight line. ∠1 +∠2 = 180° [Angles on a straight line PQ] Solution : (a) 60°, 30° In the given figure, are the following pairs of angles adjacent? (d) Vertically opposite angles are always equal. An angle is 45°. Also, m || n and p is transversal. NCERT Solutions for Class 7 Maths Chapter 5 – Lines and Angles. Sum of angles of linear pair is 180°. Fill in the blanks (c) (I) is false and (II) is true (d) both (I) and (II) are false If two angles are supplementary angles, then it is not necessary that they are always obtuse angles. 5. The supplement of an acute is always _________ angle. Solution : ⇒ x + 4x = 720° A linear pair may have two acute angles. An angle is more than 45°. ⇒ ∠2 = 180° – 75° = 105° \(\Rightarrow \quad k=\frac{90^{\circ}}{5}=18^{\circ}\) Vertically opposite angles are always Solution : Question 103: Now, QP || RS and PR is a transversal. In a pair of complementary angles, each angle cannot be more than _________ Given, complement of x° is 79°. Find the sum 2a + b. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. (a) It is given that the angles are in the ratio of 1 : 2. ⇒ 50° + ∠BCD = 180° (d) 75° Following are vertically opposite angles and linear pair in the above figure: Question 74: ∴ Its complement = 90°- 45° = 45°, Question 56. NCERT Class 7 Maths Lines and Angles. Also, LM || SR and TS is a transversal. ∴ ∠QOS = 5 ∠POR = 5 × 15° = 75°, Question 23. The measure of an angle which is four times its supplement is Linear (c) (i) is false but (ii) and (iii) are true Solution: Solution: ⇒ 2∠ABP = 180° – 46° = 134 Solution : True If one of them is one-third of the other, find the angles. NCERT Exemplar Class 9 Maths Unit 6 Lines and Angles. If the complement of an angle is 79°, then the angle will be of Question 85: ⇒ 5a = 180° + 20° = 200° (c) The angle between South and West is a right angle and angle between South and East is also a right angle. (c) alternate interior angles Find the values of a, b and c. Solution : (c) 45° In the given figure, if l || m, find the values of a and b. (b) making a linear pair (a) pair of complementary angles. In the given figure, P, Q and R are collinear points and TQ ⊥ PR, NCERT Class 7 Maths Unit 5 is for Lines and Angles. Alternate interior angles have one common_______. These NCERT Solutions for Class 7 Maths Lines and Angles in Hindi medium pdf download have innumerable benefits as these are created in simple and easy-to-understand language. Let x = 3k and y – 2k (a) all (i), (ii) and (iii) are true (b) (iii) is false Let one angle be 2x + 1, then the other angle is 2x + 3. Now, LM || QP and QT is a transversal. Find ∠QUR. NCERT Solutions for Class 7 Maths Chapter 5 – Lines and Angles Exercise 5.1 : Solutions of Questions on Page Number : 101 Q1 : Find the complement of each of the following angles: ⇒ x = 180° – 61°= 119°. Solution: Then, which one of the following is not true? Since, a and b form a linear pair. You can find NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Exercise 5.1 here that will be helpful in knowing the important points and formulas given in the exercise. ∴ 2x + 1 = 2 × 44° + 1 = 88° + 1 = 890 (iii) ∠TSV and ∠USV; ∠SVT and ∠SVU are adjacent angles. (d) Let the required angle be x°. Solution: Thus, the required angles are 60° and 30°. (ii) EF is a straight line. (b) one of its angles is obtuse? What is the type of other angle of a linear pair, if ∴ In option (d), a and b form a pair of adjacent angles. (b) Sum of the given angles = x + 90° – x = 90° In the given figure, write all the pairs of supplementary angles. In the given figure, state which pair of lines are parallel. The above Practice worksheets for Class 7 Lines and Angles have been designed as per latest NCERT CBSE and KVS guidelines and 2021 syllabus. c || f and a is transversal. (b) 50°,130° Two lines AB and CD intersect at 0 (see the figure). So, if one angle is acute, then other angle will be acute and if one angle is obtuse, then the other will be obtuse. ∴ EF and GH are not parallel lines. (ii) d and e Refer to other chapters and books at other links (NCERT now providing you soft copies of all textbooks of all subjects from class first to twelfth online). (c) 30°, 50° Question 52: ⇒ 3x = 180° – x ⇒ 3x + x = 180° Question 104. Opposite ⇒ 120° + ∠x – 180° [Using (1)] As, if we subtract an obtuse angle from 180°, then result will be an acute angle, i.e. Now, p || q and m is a transversal. Solution: It is given that other angle is one-third of first. Solution: (d) Two angles are called adjacent angles, if they have a common vertex and a common arm but no common interior points. Now, PO || ST and OS is transversal. Find ∠AOD. Solution: (d) 45°, 45° (b) how many types of angles are formed? ∴ b = 55° [Alternate interior angles] If the sum of measures of two angles is 180° then they are _________ ∴ x + 2y + 3y = 180° A linear pair is a pair of adjacent angles whose non-common sides are opposite rays. So, this player has the best kicking angle. 5. Then, which of the following is true? and ∠1 = 30°[Vertically opposite angles] In the given figure, P, Q and R are collinear points and TQ ⊥ PR. The value of a is fill in the blanks to make the statements true. NCERT Class 7 Maths Chapter 5Lines and Angles Notes have been largely compiled by teachers with near to 20 years of experience and after studying the last ten years of examination papers. Angles between South and West and South and East are An angle of a linear pair is half of a right angle. Question 35. ⇒ ∠APR = 130° ⇒ z + 36° = 180° ⇒ z = 180° – 36° = 144°, Question 31. ⇒ ∠PQU = 35° ———- (i) ⇒ 3a – b + 2a + b = 180 ⇒ 5a = 180 One obtuse angle and one acute angle can make a pair of supplementary angles, e.g. With the help of it, candidates can prepare well for the examination. (d) 120° ∴ ∠2 + 3 = 180° [Co-interior angles] Question 43: (b) Now the players are lined up as shown in figure (iii). l || m and PQ is a transversal e.g. ∠FOR + ∠QRH = 123° + 57° = 180° ∴ Its supplement = 180° – x Question 6. (c) From the above figure, ∠5 and ∠8 are alternate interior angles. (c) In the given figure, a and b are alternate interior angles as both lie on opposite sides of transverse line. Since, the difference between the two angles is 30°, then the other angle will be (x – 30°). Since, QP || RS and PR is transversal. Now, l is a straight line. We know that, sum of two complementary angles is 90°. According to question, Hence, ∠AOC and ∠BOC are supplementary angles. (b) Since, PA || BC and AB is a transversal. (b) (iii) is false In the given figure, PA || BC || DT and AB || DC. In the given figure, l || m || n. ∠OPS = 35° and ∠QRT = 55°. Solution: If an angle is 60° less than two times of its supplement, then the greater angle is A + B = 90° As, PQ is a straight line. (a) 120° (b)125° (c)110° (d)90° Find ∠EFD. ∠3 = ∠7 ∠4 = ∠8; Pairs of alternate interior angles are equal. ⇒ a = 180° – 85° = 95°. Since, angles are supplementary Hence, the sum of P and O will be 180°, Question 13: q : a and b are forming a pair of adjacent angles. In the given figure, lines l and m intersect each other at a point. (b) how many types of angles are formed? (a) Let the two angles be x and 2x. Vertically opposite angles are equal. Since, a transversal intersects two parallel lines, then interior angles on the same side of a transversal are supplementary. One obtuse angle and one acute angle can make a pair of complementary angles Solution : Solution : ⇒ ∠Q = 180° – 60° = 120°, Question 13. (d) 64° Then, which one of the following is not true? In the given figure, PQ || SR and SP|| RQ. ⇒ y = 90° – 60° = 30° Question 23: Find the value of a + b. (a) It is given that, POO is a line. (ii) EF || GH \(\frac{\angle P O R}{\angle Q O S}=\frac{1}{5}\) If ∠AOE = 30° and ∠DOB = 40° (see the figure) find ∠COF. Solution: As, if we subtract an angle which is less than 90° from 180°, then result will be an angle greater than 90°. Question 78. Find the measures of the angles. The supplement of a right angle is always_______angle. (a) Total 13 angles are formed, namely ∠AOB, ∠BOC, ∠COD, ∠DOA, ∠AOC, ∠BOD, ∠DOB, ∠AOD, ∠BOA, ∠COB, ∠DOC, ∠AOA. The angles between North and West and South and East are Question 59. Solution: Since, AE || BD and CH is a transversal. (b) making a linear pair (c) vertically opposite NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Exercise 5.1 and Exercise 5.2 in English Medium and Prashnavali 5.1 and Prashnavali 5.2 in Prashnavali to study online or download in PDF file for offline free to use. ⇒ ∠2 = (3 × 36 – b)° = (108 – b)°, Question 36. In a pair of adjacent angles, ∴ 2x = 2 × 22° = 44° and 2x + 2 = 44° +2 = 46° According to question, Solution: Solution: ⇒ 42° + ∠QUR = 180° [Using (i)] Solution: In the given figure, lines PQ and ST intersect at O. Since, l || m and p is a transversal. As two right angles are supplementary to each other. (d) ∠4 = ∠8 We have now provided you with NCERT Solutions for Class 7 Maths Chapter 5 – Lines and Angles. ∴ x + y = 85° + 50° = 135°, Question 41. Then, f is equal to In the given figure, the value of y is Solution: In the given figure, PQ || RS and a : b =3 : 2. (ii) Name all the pairs of complementary angles. In the above figure, x + y = 180°. Solution: ⇒ b = c – a (a) 120° ⇒ 4x + 4 = 180° ⇒ 4x = 180°- 4 = 176° If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles, drop a comment below and we will get back to you at the earliest. Its complementary angle will be________. Solution: Hence, a and b form a pair of adjacent angle only in (i). Same ∴ ∠a = 30° [Using (ii)] Solution: Solution : A road crosses a railway line at an angle of 30° as shown in the figure. Lines and Angles Class 7 Maths NCERT Solutions were prepared according to CBSE (NCERT) guidelines. Solution : (iii) d and f (iv) c and f False Arm (c) 36° Now, l || m and AC is a transversal. Since, both angles are complementary. Question 27: According to question, If you have any query regarding NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles, drop a comment below and we will get back to you at the earliest. (a) 95°, 85° (b) 90°, 90° The questions given in the worksheets are framed in a manner which will help to revise the entire syllabus, concepts and also develop analytical and problem solving skills in students. We have ∴ EF || GH 45° : Given, angle = 45° \(\Rightarrow \quad x=\frac{210}{6}=35\) In the given figure, POR is a line. ⇒ 4x = 90° – 2 = 88° ∴ ∠2 + 135° = 180° [Co-interior angles] Let the two interior angles on the same side of transversal are x and y. Putting value of x in (i), we get ∴ ∠PQT = ∠LTQ [Alternate interior angles] Solution : ⇒ ∠EOD = 180° -30° – 40° = 110° ——— (i) We have provided Lines and Angles Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. Question 54: Hence, two situations are 45°, 45° and 30°, 60°. ∴ AB and CD are not parallel lines. False Thus, ∠BOC = 40°, Question 101. (c) If one of the angles is right, then other angle of a linear pair is also right. No. Let the angles will be x and 2x. Both angles of a pair of supplementary angles can never be acute angles. Solution: In the given figure, PQ || RS, TR || QU and ∠PTR = 42°. Solution : ⇒ 5b + 2 × 40° = 180° In the given figure, lines PQ and ST intersect at 0. ∠3 + ∠8 = 180° ——– (ii) [Co-interior angles] (c) 100°, 60° Since, the sum of given two angles is 90°. (a) 4th player has the greatest kicking angle. In the given figure, ∠ROS is a right angle and ∠POR and ∠QOS are in the ratio 1 : 5. NCERT Exemplar Class 7 Maths Chapter 5 Lines and Angles are part of NCERT Exemplar Class 7 Maths. ∴ AOB is a straight line. Question 102: The value of b is (c) adjacent CBSE Worksheets for Class 7 Maths: One of the best teaching strategies employed in most classrooms today is Worksheets. Then, AOB will be a straight line and sum of all the angles on a straight line is 180°. (a) All (i), (ii) and (iii) are true ⇒ 60° + 20 = 180° Since, PQ || RT and PR is a transversal. (a) 95°, 85° Angles, which are both supplementary and vertically opposite are We have, (iii) uncommon arms are always opposite rays. (c) PQ || RS, line l is a transversal. x + 61° = 180° [Linear pair] ∴ b = 48° ——— (i) (c) If one angle is right angle, then other angle will also be right angle. (b) 67° Solution : In the given figure, ∠AOC and ∠BOC form a pair of Find each of the angles. Solution: Question 60: (b) Statement a is true but statement b is false since, if a transversal intersects two parallel lines, then the sum of two interior angles on the same side of the transversal is 180°. (d) both a and b are false Give reason in support of your answer. Thus, one angle is 100° and other is 80°. (d) 135° (a) 5b + 2a = 180° [Linear pair] ; Question 24: Directions: In questions 42 to 56, fill in the blanks to make the statements true. (d) 120° Question 50: (ii) Let the angle between d and e is ∠2. Solution : ⇒ x = 360° – 2x – 60° alternate Interior angles are on the _________ side of the transversal. Question 66: Obtuse (c) Draw a line L.M passing through T such that LM || QP || SR. Find the angles. Statements a and bare as given below: NCERT Exemplar Class 7 Maths Book PDF Download Chapter 12 Practical Geometry Symmetry and Visualising Solid Shapes Solutions Multiple Choice Questions (MCQs) Question 1: A triangle can be constructed by taking its sides as (a) 1.8 cm, 2.6 cm, 4.4 cm (b) 2 … ⇒ 2x = 180° ⇒ x = 90° ∴ ∠TQS and ∠SQR are pair of complementary angles, as their sum is 90°. True, Question 69. Which of the following is false? MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. Solution : If the complement of an angle is 799, then the angle will be of I: If two lines intersect, then the vertically opposite angles are equal. The value of bis (c) ∠a + ∠d = 180° From the above figure, we can say that player 4 has the best kicking angle, as it is greatest. \(\Rightarrow a=\frac{50^{\circ}}{5}=10^{\circ}\), Question 27. a and b are on the opposite side of transversal l. Solution: Write all the pairs of adjacent angles by taking angles 1, 2, 3 and 4 only. Question 68: ⇒ 90° + x + y = 180° In the given figure, PO || RS, TR || QU and ∠PTR = 42°. (b) 90° True, Question 62. Solution : ∴ ∠ABP = ∠CBQ ——– (1) (b) Since, ∠POR, ∠ROT and ∠TOQ lies on a straight line POQ, then their sum is equal to 180°. Find the values of a, b and c. Name; 100° + y = 180 ⇒ y = 180° – 100° = 80° Solution : In exercise 1 there are 8 questions, in exercise 2 there are 10 questions in total, exercise 3 has 10 questions and exercise 4 has 7 … The angle The angles x and 90° – x are RD Sharma Class 11 Solutions Free PDF Download, NCERT Solutions for Class 12 Computer Science (Python), NCERT Solutions for Class 12 Computer Science (C++), NCERT Solutions for Class 12 Business Studies, NCERT Solutions for Class 12 Micro Economics, NCERT Solutions for Class 12 Macro Economics, NCERT Solutions for Class 12 Entrepreneurship, NCERT Solutions for Class 12 Political Science, NCERT Solutions for Class 11 Computer Science (Python), NCERT Solutions for Class 11 Business Studies, NCERT Solutions for Class 11 Entrepreneurship, NCERT Solutions for Class 11 Political Science, NCERT Solutions for Class 11 Indian Economic Development, NCERT Solutions for Class 10 Social Science, NCERT Solutions For Class 10 Hindi Sanchayan, NCERT Solutions For Class 10 Hindi Sparsh, NCERT Solutions For Class 10 Hindi Kshitiz, NCERT Solutions For Class 10 Hindi Kritika, NCERT Solutions for Class 10 Foundation of Information Technology, NCERT Solutions for Class 9 Social Science, NCERT Solutions for Class 9 Foundation of IT, PS Verma and VK Agarwal Biology Class 9 Solutions, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, Periodic Classification of Elements Class 10, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10. Mathematics NCERT Grade 7, Chapter 5: Lines and Angles is all about different lines, line segments, and angles. Question 71. In the given figure, two parallel lines l and m are cut by two transversals p and 4. Solution : Note Sum of the complementary angles is 90°. Hence, a = 65° and b = 70°. ⇒ ∠RSC = 180° – 65° = 115° It is given that, the angle is four times its supplement. (c) 122° (d) 119° Now, p || q and n is a transversal. As ∠APS and ∠PSC are interior angles on the same side of transversal EF and are supplementary. In parts (a) and (b) given below, it may help to trace the diagrams and draw and measure angles. Question 54: in the given figure it is given that x° makes a linear pair time... Is 166° 7 can download these Solutions is a right angle is more 45°! If x = 110° [ Alternate interior angles have one common_______ both angles of a right angle these at! 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